The sequence diverges because the series divergence the limit tends to infinity does not exist option (A) is correct.
What is the convergent of a series?
A series is convergent if the series of its partial sums approaches a limit; that really is, when the values are added one after the other in the order defined by the numbers, the partial sums get closer and closer to a certain number.
We have:
A sequence:
[tex]\rm a_n=\dfrac{\left(n^3-n\right)}{n^2+5n}[/tex]
As we know if the series converges the limit tends to infinity exist.
If the series divergence the limit tends to infinity does not exist.
Taking limit x tends to infinity:
[tex]\rm = \lim \:_{n\to \:\infty \:\:}\dfrac{\left n^3-n\right}{n^2+5n}[/tex]
[tex]\rm =\lim _{n\to \infty \:}\left(\dfrac{n^2-1}{n+5}\right)[/tex]
[tex]\rm =\lim _{n\to \infty \:}\left(\dfrac{n-\frac{1}{n}}{1+\dfrac{5}{n}}\right)[/tex]
[tex]\rm =\dfrac{\lim _{n\to \infty \:}\left(n-\dfrac{1}{n}\right)}{\lim _{n\to \infty \:}\left(1+\dfrac{5}{n}\right)}[/tex]
= ∞/1
= ∞ = does not exist.
Thus, the sequence diverges because the series divergence the limit tends to infinity does not exist option (A) is correct.
Learn more about the convergent of a series here:
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