Answer:
[tex]1100\:\mathrm{J}\text{ or }1.1\cdot 10^3\:\mathrm{J}[/tex]
Explanation:
Specific heat capacity is given by [tex]Q=mc\Delta T[/tex], where [tex]Q[/tex] is thermal energy, [tex]m[/tex] is the mass of the substance, [tex]c[/tex] is the specific capacity, and [tex]\Delta T[/tex] is change in temperature.
What we know:
- mass [tex]m[/tex] of 0.2 kg
- change in temperature of [tex]12^{\circ}[/tex] Celsius
- Iron's specific heat capacity is 462 Joules per kilogram per Kelvin
*When solving, make sure to convert all units into their respective SI units
Substituting known values, we get:
[tex]Q=0.2\cdot 12\cdot 462,\\Q=1106.4\:\mathrm{J}\approx\boxed{1100\:\mathrm{J}}[/tex]
