Question

13*d = 1 mod 60 PLEASE WITH STEPS I WILL GIVE BRAINLIST​

Answer 1

Answer:

$d=37+60k, k\in\mathbb{R}$

Step-by-step explanation:

Modulo can be read as:

For $x\mod y$, what is the remainder when $x$ is divide by $y$?

Therefore, we're looking for a number that when divided by 60 returns a remainder of 1.

Compare multiples of 13 and 60 to find a pair where the multiple of 13 is exactly 1 greater than the multiple of 60.

After some digging, we find that

$481-1=0\mod60,\\481=1\mod60$

Therefore, we can substitute $1\mod 60$ with $481$:

$13\cdot d=481,\\d=\boxed{37}$

Since there are clearly more than one number that when divided by 60 returns a remainder of 1, any valid answer $\pm$60 will also be a valid answer. Therefore, $d=37+60k$, for all real numbers $k$.