Answer:
The angle of inclination of the rider to the vertical is 32.5⁰.
Explanation:
Given;
linear speed of the motor cycle, v = 90 km/hr = 25 m/s
radius of the circle, r = 100 m
The angle of inclination of the rider to the vertical is calculated using banking angle formula;
[tex]\theta = tan^{-1}(\frac{v^2}{rg} )\\\\\theta = tan^{-1} (\frac{25^2}{100 \times 9.8} )\\\\\theta = 32.5 ^0[/tex]
Therefore, the angle of inclination of the rider to the vertical is 32.5⁰