Respuesta :

Let's find the slope of the line passing through it :

[tex] \boxed{ slope = \frac{y_2-y_1}{ x_2- x_1} }[/tex]

  • [tex] \dfrac{ -5 - ( - 6)}{0 - ( - 5)} [/tex]

  • [tex] \dfrac{1}{5} [/tex]

Now, we know, equation of a line is :

[tex]\longrightarrow y = mx + b[/tex]

where,

  • m represents the slope

Therefore,

[tex]\longrightarrow \: y = \dfrac{1}{5} x + b[/tex]

let's put the value of x and y from the first coordinates .

  • [tex]y = \dfrac{x}{5} + b[/tex]

  • [tex] - 5 = \dfrac{0}{5} + b[/tex]

  • [tex]b = - 5[/tex]

Hence, we got the equation of line as :

  • [tex]y = \dfrac{x}{5} - 5[/tex]

or

  • [tex]5y = x - 25[/tex]

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[tex]\mathrm{ ☠ \: TeeNForeveR \:☠ }[/tex]

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