Let's find the slope of the line passing through it :
[tex] \boxed{ slope = \frac{y_2-y_1}{ x_2- x_1} }[/tex]
- [tex] \dfrac{ -5 - ( - 6)}{0 - ( - 5)} [/tex]
- [tex] \dfrac{1}{5} [/tex]
Now, we know, equation of a line is :
[tex]\longrightarrow y = mx + b[/tex]
where,
Therefore,
[tex]\longrightarrow \: y = \dfrac{1}{5} x + b[/tex]
let's put the value of x and y from the first coordinates .
- [tex]y = \dfrac{x}{5} + b[/tex]
- [tex] - 5 = \dfrac{0}{5} + b[/tex]
Hence, we got the equation of line as :
- [tex]y = \dfrac{x}{5} - 5[/tex]
or
_____________________________
[tex]\mathrm{ ☠ \: TeeNForeveR \:☠ }[/tex]