Answer:
[tex] \alpha = 108\degree, \: \beta = 72\degree [/tex]
Step-by-step explanation:
α and β are Supplementary (given)
[tex] \therefore \alpha + \beta = 180\degree.... (1)[/tex]
It is given that:
[tex] \alpha= \frac{3}{2} \beta[/tex]
Plugging the value of α in equation (1), we find:
[tex] \frac{3}{2} \beta + \beta = 180\degree[/tex]
[tex]\therefore \frac{3+2}{2} \beta = 180\degree[/tex]
[tex]\therefore \frac{5}{2} \beta = 180\degree[/tex]
[tex]\therefore \beta = 180\degree\times \frac{2}{5}[/tex]
[tex]\therefore \beta = 72\degree[/tex]
[tex]\implies \alpha= \frac{3}{2} \times 72\degree= 108\degree [/tex]
So,
[tex] \alpha = 108\degree, \: \beta = 72\degree [/tex]