Question

if the area is 14.3yd, what is b?1?

Answer 1

Given:

The figure of a trapezoid.

Area of the trapezoid = 14.3 square yd.

To find:

The value of first base, i.e., $b_1$.

Solution:

From the given figure, it is clear that

Vertical height = 2.6 yd

Second base = 7.9 yd

The area of a trapezoid is:

$A=\dfrac{1}{2}(b_1+b_2)h$

Putting $b_2=7.9,\ h=2.6,\ A=14.3$ in the above formula, we get

$14.3=\dfrac{1}{2}(b_1+7.9)(2.6)$

$2\times 14.3=(b_1+7.9)(2.6)$

$28.6=2.6b_1+20.54$

Isolate the variable term.

$28.6-20.54=2.6b_1$

$8.06=2.6b_1$

$\dfrac{8.06}{2.6}=b_1$

$3.1=b_1$

Therefore, the value of $b_1$ is equal to 3.1 yd.