Answer:
6.25 gram
Explanation:
Applying,
R = R'([tex]2^{a/n}[/tex])................ Equation 1
Where R = Original mass of the isotope, R' = mass of the isotope left after disintegration, a = Total time, n = half life.
make R' the subject of the equation
R' = R/([tex]2^{a/n}[/tex])................. Equation 2
From the question,
Given: R = 100 gram, a = 20 munites, n = 5 minutes.
Substitute these values into equation 2
R' = 100/([tex]2^{20/5}[/tex])
R' = 100/[tex]2^{4}[/tex]
R' = 100/16
R' = 6.25 gram