Respuesta :

Answer:

6.25 gram

Explanation:

Applying,

R = R'([tex]2^{a/n}[/tex])................ Equation 1

Where R = Original mass of the isotope, R' = mass of the isotope left after disintegration, a = Total time, n = half life.

make R' the subject of the equation

R' = R/([tex]2^{a/n}[/tex])................. Equation 2

From the question,

Given: R = 100 gram, a = 20 munites, n = 5 minutes.

Substitute these values into equation 2

R' = 100/([tex]2^{20/5}[/tex])

R' = 100/[tex]2^{4}[/tex]

R' = 100/16

R' = 6.25 gram

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