Question

In parallelogram ABCD shown, point E and F are located on diagonal BD and point G is located on side AB such that GE and CF are perpendicular to BD. Prove: trainge BEG is similar to traingle DFC​

Answer 1

Answer:

Match the Statement number with the Reason number.

Step-by-step explanation:

Statements:

1.GE is perpendicular to BD

CF is perpendicular to BD

2. Angle GED equal 90

Angle DFC equal 90

3. Angle GED is congruent to Angle DFC

4. Angle GBE is congruent to Angle FDC

5. Triangle BEG is similar to DFC

Reasons:

1.Given

2. Definition of perpendicular lines

3. Transitive property

4. Alternate Interior Angles

5. AA Similarity

Answer 2

By satisfying essential conditions for two triangles to be similar, we can say that triangle BEG is similar to triangle DFC.

What is a parallelogram?

A quadrilateral in which opposites sides are equal and parallel. Also, opposite angles are equal to each other.

As we know that AB║ DC

so,∠GBE = ∠CDF (alternate angles)

∠GEB= ∠DFC = 90°

so triangle BEG≈DFC​

Therefore, we can say that triangle BEG is similar to triangle DFC

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