Question

3. Suppose you take a pendulum with length L and mass m having a period T to a
planet where the value of g is 176 of the value on Earth. What would be the period
of the pendulum on the planet? *
T/6
OT
O 1.6T
2.4 T
4.6 T
help fast

Answer 1

(C)

Explanation:

$t = 2\pi \sqrt{ \frac{l}{g} }$

If g is only 1/6 on another planet, then

$t = 2\pi \sqrt{ \frac{l}{ \frac{g}{6} } } = 2\pi \sqrt{ \frac{6l}{g} }$

$= \sqrt{6} \: (2\pi \sqrt{ \frac{l}{g} } ) = 2.4 \times t(on \: earth)$