Question

Let's say that you were given the following
problem:
A gas that exerts a pressure of 151 mm Hg in a
container with a volume of L will exert a
pressure of 166 mm Hg when transferred to a
container with a volume of 0.532 L.
Let's begin by assigning our variables. Let's say
that P1 = 151 mm Hg. What is V2?

Answer 1

Answer:

V2~0.4839M

Explanation:

We're going to use Boyles law to answer the question.

Boyle's law:

P1V1=P2V2

P1=151mmHg

P2=166mmHg

V1=0.532L

V2=?

V2=(P1 x V1)/P2

V2=(151 x 0.532)/166

V2~0.4839M

Hope it helps:)