Answer:
[tex] \frac{2}{x - 3} - \frac{12}{ {x}^{2} - 9} \\ = \frac{2}{x - 3} - \frac{12}{(x - 3)(x + 3)} \\ = \frac{2(x + 3) - 12}{( {x}^{2} - 9)} \\ = \frac{2x - 6}{( {x}^{2} - 9)} \\ = \frac{2(x - 3)}{(x - 3)(x + 3)} \\ = \frac{2}{x + 3} [/tex]
