Question

solve M2 + 6m = -8 using quadratic formula??​

Answer 1

Answer:

m=-4,-2

Step-by-step explanation:

Hi there!

What we need to know:

• The quadratic formula: $x=\frac{-b\pm\sqrt{b^2-4ac} }{2a}$ where the equation is given in standard form
• Standard form quadratic equation: $y=ax^2+bx+c$ (with y=0)

1) Rearrange the given equation into standard form

This will help us determine the a, b and c values.

$m^2+6m=-8$

Add 8 to both sides

$m^2+6m+8=0$

Now, we can see that a=1, b=6 and c=8.

2) Plug a, b and c into the quadratic formula

$m=\frac{-b\pm\sqrt{b^2-4ac} }{2a}\\m=\frac{-6\pm\sqrt{6^2-4(1)(8)} }{2(1)}\\m=\frac{-6\pm\sqrt{4} }{2}\\m=\frac{-6\pm2 }{2}\\m=-3\pm1 \\m=-4,-2$

I hope this helps!