Respuesta :

[tex] \huge\boxed{ \boxed{\mathrm{ \underline{Answer}࿐ }}}[/tex]

The given triangle is a right angled triangle,

so let's apply trigonometry here :

  • [tex] \sin(30) = \dfrac{7}{y} [/tex]

  • [tex] \dfrac{1}{2} = \dfrac{7}{y} [/tex]

  • [tex]y = 7 \times 2[/tex]

  • [tex]y = 14 \: \: units[/tex]

Now,

  • [tex] \cos(30) = \dfrac{x}{y} [/tex]

  • [tex] \dfrac{ \sqrt{3} }{2} = \dfrac{x}{14} [/tex]

  • [tex]x = \dfrac{14 \sqrt{3} }{2} [/tex]

  • [tex]x = 7 \sqrt{3} [/tex]

  • [tex]x = 12.12 \: \: units[/tex]

_____________________________

[tex]\mathrm{ ☠ \: TeeNForeveR \:☠ }[/tex]

x = 7√3 & y = 14

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