Answer: The volume of the balloon up there is 6.192 L.
Explanation:
Given: [tex]V_{1}[/tex] = 1.80 L, [tex]P_{1}[/tex] = 785 mm Hg (mm Hg = 0.00131579) = 1.032 atm
[tex]P_{2}[/tex] = 0.300 atm, [tex]V_{2}[/tex] = ?
Formula used to calculate volume is as follows.
[tex]P_{1}V_{1} = P_{2}V_{2}[/tex]
Substitute the value into above formula as follows.
[tex]P_{1}V_{1} = P_{2}V_{2}\\1.032 atm \times 1.80 L = 0.300 atm \times V_{2}\\V_{2} = 6.192 L[/tex]
Thus, we can conclude that the volume of the balloon up there is 6.192 L.