Respuesta :

Answer:1.12 g

Explanation:Molar mass of compound ​FeSO4(NH4)2SO4.6H2O = 392.14 g mol-1

Number of moles of compound in 7.84g sample = 7.84 g/ 392.14 g mol-1

                                                                       = 0.02 mole

1 mole of sample contain 1 mole of Fe

So, 0.02 mole of sample would contain 0.02 moles of Fe.

Mass of Fe equivalent to 0.02 mole = 0.02 mol x molar mass of Fe

                                                    = 0.02 mol x 55.84 g mol-1

                                                   = 1.12 g

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