Answer:
- [tex]\frac{1}{3}[/tex]
Step-by-step explanation:
[tex]\frac{2x-3y}{2x+3y}[/tex] ← factor out y from each term on numerator/ denominator
= [tex]\frac{y(2\frac{x}{y} -3)}{y(2\frac{x}{y} +3)}[/tex]
= [tex]\frac{2(\frac{3}{4})-3 }{2(\frac{3}{4})+3 }[/tex]
= [tex]\frac{\frac{3}{2}-3 }{\frac{3}{2}+3 }[/tex]
= [tex]\frac{-\frac{3}{2} }{\frac{9}{2} }[/tex]
= - [tex]\frac{3}{2}[/tex] × [tex]\frac{2}{9}[/tex]
= - [tex]\frac{3}{9}[/tex]
= - [tex]\frac{1}{3}[/tex]
