Given :
Magnitude of vector, v = 15.3 m
Angle of vector from horizon, [tex]\theta = 65^o[/tex] .
To Find :
The x - component of the given vector.
Solution :
We know, a vector is given by :
[tex]\vec{v} = vsin\ \theta \hat{i} + v cos \ \theta \hat{j}\\[/tex]
Now, the x - component is :
[tex]\vec{v_x} = vcos\ \theta \hat{j}\\\\\vec{v_x} = 15.3 \times cos\ 65^o \hat{j}\\\\\vec{v_x} = 15.3 \times 0.42\ \hat{j}\\\\\vec{v_x} = 6.426\ \hat{j}[/tex]
Hence, this is the required solution.
