Question

3. A force of 90N pushes downward at an angle of 32° to the horizontal on an object resting on the floor. The
object does not move. If the Normal force acting upward is 200 N find the weight of the object. (Ans. 152 N)
not sure how I would set this question up

Answer 1

F = m × g

Now when, a force acts on the object at an angle and in downwards, thus formula becomes:

= N = mg + F sin(x)

Here,

• N = normal force, m = mass , g = acceleration due to gravity, F = outside force, x = the angle formed

See, as we habe to calculate the weight, which is m × g, thus we will recreate thus formula like thus:

= N = w + F sin(x) --------- [Weight = w]

Now, the solutions becomes easy from here, just put the values:

= N = w + F sin(x)

= 200 = w + 90 × sin(32)

= 200 = w + 90 × 0.55

= 200 = w + 49.5

= 200 - 49.5 = w

= 150.5 = w

I have got my answer but in approx, hope you will not mind. ^^"