Answer:
B
Explanation:
There's a three in front of the CH3COOH. But let's figure it out without that 3.
1 mol of CH3COOH has 3 H from CH3 and 1 hydrogen at the end. In all 4 hydrogens.
Now put the 3 in front 3CH3COOH multiplies everything by 3. So you had 4 before and with the 3 in front you must have 12.
Try it. Draw it out.
CH3COOH has 4
CH3COOH has 4
CH3COOH has 4
Total 12
That's B
