Answer:
24.24 g
Explanation:
First we calculate how many moles are there in 300 mL of a 0.234 M solution, using the definition of molarity:
Converting 300 mL to L ⇒ 300 mL / 1000 = 0.300 L
Then we convert 0.78 moles of NH₄F into grams, using its molar mass: