In the experiment, a meter is hooked up to a speaker to monitor the amplitude of the received sound. Suppose the background signal level is 13 mV, the signal is 91 mV with no attenuator and is 25 mV with an attenuator in place. Calculate pt/pi including the background correction.

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Answer:

The answer is "[tex]15.38\%[/tex]"

Explanation:

Background[tex]= 13 \ mv\\\\[/tex]

corrected signal[tex]= 91 \ mv-13\ mv= 78\ mv\\\\[/tex]

with attenuator[tex]=25\ mv-13\ mv= 12\ mv\\\\[/tex]

[tex]\to \frac{p_t}{p_i}=\frac{12}{78}\times 100= 15.38\%[/tex]

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