Answer:
the half-life of the compound is 223 minutes
Explanation:
Given the data in the question;
compound decomposes by a first-order process,
17% of compound decomposes in 60 minutes,
the half-life of the compound = ?
Since its a first order reaction, we use the expression;
k = 1/t ln( Co/Cf )
given that; t = 30 minutes, Cf = 1 - 17% of Co = 1 - 0.17 of Co = 0.83Co
we substitute
k = ( 1 / 60 min ) ln( Co / 0.83Co )
k = ( 1 / 60 min ) ln( 1 / 0.83 )
k = 0.016667 × 0.186329578
k = 0.003105555
so get the half life;
[tex]t_{1/2[/tex] = 0.693 / k
we substitute
[tex]t_{1/2[/tex] = 0.693 / 0.003105555
[tex]t_{1/2[/tex] = 223.14 ≈ 223 minutes
Therefore, the half-life of the compound is 223 minutes