Question

If g of chlorine gas occupies a volume of mL at a particular temperature and pressure, what volume will g of chlorine gas occupy under the same conditions

Answer 1

The complete question is as follows: If 1.04 g of chlorine gas occupies a volume of 872 mL at a particular temperature and pressure, what volume will 2.08 g of chlorine gas occupy under the same conditions ?

Answer: A volume of 1744 L will 2.08 g of chlorine gas occupy under the same conditions.

Explanation:

Given: $Mass_1$ = 1.04 g,      $V_{1}$ = 872 mL

$Mass_2$ = 2.08 g,                $V_{2}$ = ?

As molar mass of chlorine is 35.5 g/mol.

Number of moles is the mass of a substance divided by its molar mass.

Hence, moles of chlorine present in 1.04 g chlorine gas is calculated as follows.

$Moles = \frac{mass}{molar mass}\\= \frac{1.04 g}{35.5 g/mol}\\= 0.029 mol$

Also, moles of chlorine present in 2.08 g chlorine gas is calculated as follows.

$Moles = \frac{2.08 g}{35.5 g/mol}\\= 0.058 mol$

Formula used to calculate the volume occupied by 2.08 g of chlorine gas is as follows.

$\frac{V_{1}}{n_{1}} = \frac{V_{2}}{n_{2}}$

Substitute the values into above formula as follows.

$\frac{V_{1}}{n_{1}} = \frac{V_{2}}{n_{2}}\\\frac{872 L}{0.029 mol} = \frac{V_{2}}{0.058 mol}\\V_{2} = 1744 L$

Thus, we can conclude that a volume of 1744 L will 2.08 g of chlorine gas occupy under the same conditions.