Question

Water has a heat capacity of 4.184 J/g °C. If 50 g of water has a temperature of 30°C and a piece of hot copper is added to the water causing the temperature to increase to 70°C. What is the amount of heat absorbed by the water?​

Answer 1

Answer:

Q = 8368 Joules.

Explanation:

Given the following data;

Mass = 50 g

Initial temperature = 30°C

Final temperature = 70°C

Specific heat capacity = 4.184 J/g °C

To find the amount of heat absorbed by the water;

Heat capacity is given by the formula;

$Q = mcdt$

Where;

Q represents the heat capacity or quantity of heat.

m represents the mass of an object.

c represents the specific heat capacity of water.

dt represents the change in temperature.

dt = T2 - T1

dt = 70 - 30

dt = 40°C

Substituting the values into the equation, we have;

$Q = 50*4.184*40$

Q = 8368 Joules.