Answer: 1.67 m/s
Explanation:
Given
Mass of bag is [tex]m=8.6\ kg[/tex]
Mass of cart is [tex]M=18.1\ kg[/tex]
bag hits the cart with horizontal speed of [tex]u=5.2\ m/s[/tex]
Suppose the system move with speed v after collision
Conserving the momentum
[tex]\Rightarrow mu+M(0)=(M+m)v\\\\\Rightarrow v=\dfrac{mu}{M+m}\\\\\Rightarrow v=\dfrac{8.6\times 5.2}{18.1+8.6}\\\\\Rightarrow v=1.67\ m/s[/tex]