A nearsighted person has a far point of 25.525.5cm and is prescribed contact lenses to correct her vision. What lens strength (a.k.a., lens power), in Diopters, should be prescribed

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Answer:

The right answer is "-3.90 D".

Explanation:

According to the question,

Far point,

v = -25.525 cm

and,

u = [tex]\infty[/tex]

By using the lens formula, we get

⇒ [tex]\frac{1}{f} =\frac{1}{v} -\frac{1}{u}[/tex]

On putting the values, we get

⇒     [tex]=\frac{1}{-25.525} +\frac{1}{\infty}[/tex]

⇒  [tex]f=-25.525 \ cm[/tex]

or,

⇒     [tex]=-25.6 \ cm[/tex]

hence,

⇒ [tex]Power (P)=\frac{100}{f}[/tex]

⇒                  [tex]=\frac{100}{-25.6}[/tex]    

⇒                  [tex]=-3.90 \ D[/tex]

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