Question

Solve using the quadratic formula. Approximate answers to the nearest tenth.

Answer 1

Answer:

$\displaystyle x\approx -1.4\text{ or } 2.9$

Step-by-step explanation:

We want to solve the equation:

$\displaystyle 2x^2-3x-8=0$

Using the quadratic formula.

The quadratic formula is given by:

$\displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

In this case, a = 2, b = -3, and c = -8. Substitute:

$\displaystyle x=\frac{-(-3)\pm\sqrt{(-3)^2-4(2)(-8)}}{2(2)}$

Evaluate:

$\displaystyle x=\frac{3\pm\sqrt{73}}{4}$

So, our solutions are:

$\displaystyle x=\frac{3+\sqrt{73}}{4}\approx 2.9\text{ and } x=\frac{3-\sqrt{73}}{4}\approx-1.4$