Answer:
[tex]x=6,\\m\angle 1=18^{\circ}[/tex]
Step-by-step explanation:
Since the problem denotes the figure as a parallelogram, [tex]\overline{AB}[/tex] is parallel to [tex]\overline{DC}[/tex]. Therefore, angles 1 and 2 are equal (from corresponding angles and vertical angles).
Therefore, we have the following equation:
[tex]m\angle 1=m\angle 2,\\x+12=6x-18,\\30=5x,\\x=\boxed{6}[/tex]
Substituting [tex]x=6[/tex]:
[tex]m\angle 1=x+12=6+12=\boxed{18^{\circ}}[/tex]
