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Calculate the gravitational force of attraction betweentwo 55 kg people who are standing 0.25 m apart.

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Answer:

F=GMm/r²

G=6.67x10^-11

F= 6.67x10^-11 x 55 x 55/(0.25)²

=3.228 x 10^-6N

The gravitational force of attraction between the two people is 3.23 × 10⁻⁶ N

From Newton's law of universal gravitation formula, we have that

[tex]F = G\frac{m_{1}m_{2} }{r^{2} }[/tex]

Where F is the gravitational force

G is the gravitational constant (G = 6.67408 × 10⁻¹¹ m³.kg⁻¹.s⁻²)

m₁ is the mass of object 1

m₂ is the mass of object 2

and r is the distance between the centers of the masses

From the question

m₁ = 55 kg

m₂ = 55 kg

r = 0.25 m

Putting the parameters into the formula, we get

[tex]F = 6.67408 \times 10^{-11} \times \frac{55 \times 55}{0.25^{2} }[/tex]

∴ F = 3.23 × 10⁻⁶ N

Hence, the gravitational force of attraction between the two people is 3.23 × 10⁻⁶ N

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