Answer:
[tex]\text{a) }30+14t\leq 110,\\\text{b) }5,\\\text{c) The maximum number of tickets the group of friends can buy is 5.}[/tex]
Step-by-step explanation:
a) Let [tex]t[/tex] represent the number of tickets they can buy. We have the following inequality:
[tex]30+14t\leq110[/tex]
b) Solving, we get:
[tex]30+14t\leq110,\\14t\leq110,\\t\leq \left\lfloor \frac{80}{14}\right \rfloor,\\ t\leq \boxed{5}[/tex]
c) The maximum number of tickets the group of friends can buy is 5.
