The value of b if 3/2 is the axis of symmetry for the graph of the function f(x)=3x2+bx+4 is -9
How to calculate the axis of symmetry of a function?
The standard equation of a function in vertex form is given as:
f(x) = (a + x)^2 + h
Given the function f(x)=3x^2+bx+4 with an axis of symmetry of 3/2, the vertex is expressed as:
3/2= -b/2a
-b/2(3)=3/2
-b/6=3/2
Cross multiply
-2b = 18
-b=9
Hence the value of b if 3/2 is the axis of symmetry for the graph of the function f(x)=3x2+bx+4 is -9
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