Question

50 POINTS
Solve the system of equations
y=2/3x + 4
2x - 3y=3

A: Infinite Solutions


B: No Solution


C: (3,2)


D: (2,-3)

Answer 1

Answer:

B) no solution

Step-by-step explanation:

this can be solved by substitution method

y= ⅔x + 4. (equation 1)

and 2x-3y= 3. (equation 2)

substitute for y into equation 2

2x-3(2/3x + 4) = 3

2x - 2x -12=3

0=15

this is a no solution equation

Answer 2

Here

• a_1=2/3
• a2=2
• b1=-1
• b2=-3
• c1=4
• c2=3

$\\ \sf\Rrightarrow \dfrac{a_1}{a_2}=\dfrac{2/3}{2}=\dfrac{1}{3}$

$\\ \sf\Rrightarrow \dfrac{b_1}{b_2}=\dfrac{1}{3}$

$\\ \sf\Rrightarrow \dfrac{c_1}{c_2}=\dfrac{-4}{3}$

As

$\\ \sf\Rrightarrow \dfrac{a_1}{a_2}=\dfrac{b_1}{b_2}\neq \dfrac{c_1}{c_2}$

It has no solutions