Question

Calculate the force of kinetic friction on a 12.3 kg mass if its coefficient of kinetic friction is 0.137

Answer 1

Answer:

Explanation:

All we need here is the equation for frictional force, which is

f = μ$F_n$ where $F_n=mg$ That's normal force which is the same thing as weight.

Therefore,

$F_n=(12.3)(9.8)$ to 2 sig figs so

$F_n=120$ and

f = (.137)(12) to 2 sig figs as well so

f = 16N