Answer:
(- 2, 4 )
Step-by-step explanation:
Given the 2 equations
3x + 5y = 14 → (1)
y = [tex]\frac{1}{2}[/tex] x + 5 → (2)
Substitute y = [tex]\frac{1}{2}[/tex] x + 5 into (1)
3x + 5([tex]\frac{1}{2}[/tex] x + 5) = 14
3x + [tex]\frac{5}{2}[/tex] x + 25 = 14
[tex]\frac{11}{2}[/tex] x + 25 = 14 ( subtract 25 from both sides )
[tex]\frac{11}{2}[/tex] x = - 11 ( multiply both sides by 2 )
11x = - 22 ( divide both sides by 11 )
x = - 2
Substitute x = - 2 into (2) for corresponding value of y
y = [tex]\frac{1}{2}[/tex] × - 2 + 5 = - 1 + 5 = 4
solution is (- 2, 4 )
