Answer:
[tex]\text{1. } v=16t+\frac{h-c}{t},\\\text{2. }90\:\mathrm{ft/s}, \\\text{3. Cannot be determined}[/tex]
Step-by-step explanation:
1. The initial equation given to us is [tex]h=-16t^2+vt+c[/tex]. Rearranging the equation to isolate [tex]v[/tex], we have:
[tex]vt=16t^2+h-c,\\\boxed{v=16t+\frac{h-c}{t}}[/tex]
2. Using the equation we rearranged in part 1, we can substitute given values:
[tex]v=16(3)+\frac{131-5}{3},\\v=48+42=\boxed{90\:\mathrm{ft/s}}[/tex]
3. We see from our equation in part 1 ([tex]v=16t+\frac{h-c}{t}[/tex]) that when [tex]t=0[/tex], the denominator of our fraction will be equal to 0. Since we cannot divide by 0, the velocity remains undefined and cannot be determined.
