Answer:
The answer is "[tex]\frac{7\sqrt{3}}{2}[/tex]"
Step-by-step explanation:
[tex]\to \sin 60^{\circ} = \frac{x}{7} \\\\\to x=\sin 60^{\circ} \times 7 \\\\\therefore \sin 60^{\circ} = \frac{\sqrt{3}}{2} \\\\\to x= \frac{\sqrt{3}}{2}\times 7 \\\\\to x= \frac{7\sqrt{3}}{2}[/tex]
