If your end product is 1.5 moles of KMnO4, how many moles of manganese oxide were used in the reaction?

The equation for the production of potassium permanganate is as follows:

2 MnO2 + 4 KOH + O2 → 2 KMnO4 + 2 KOH + H2
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Answer:

1.5 moles of KMnO4 will be produced from 1.5 moles of MnO2

Explanation:

The balanced equation of this chemical reaction is

2 MnO2 + 4 KOH + O2 → 2 KMnO4 + 2 KOH + H2

2 moles of MnO2 produces 2 moles of   KMnO4

That means 1 moles of KMnO4 will be produced from 1 moles of MnO2

Hence, 1.5 moles of KMnO4 will be produced from 1.5 moles of MnO2

The moles of manganese oxide were used in the reaction is 1.5 moles.

What is stoichiometry?

Stoichiometry of any reaction tells about the relative amount of species present before and after the chemical reaction.

Given chemical reaction is:

2MnO₂ + 4KOH + O₂ → 2KMnO₄ + 2KOH + H₂

From the stoichiometry of the reaction, it is clear that same moles of manganese oxide and potassium permanganate is involved in the reaction.

2 moles of KMnO₄ = produce by 2 moles of MnO₂

1.5 moles of KMnO₄ = produce by 2/2×1.5=1.5 moles of MnO₂

Hence, required moles are 1.5 moles.

To know more about moles, visit the below link:

https://brainly.com/question/24631381

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