Question

find the first term in a geometric sequence in which the common ratio is 5/2 and the tenth is 625/16

Answer 1

Step-by-step explanation:

$r = \frac{5}{2} \\ a {r}^{9} = \frac{625}{15} \\ \frac{1953125a}{512} = \frac{625}{15} \\ this \: question \: has \: a \: problem$