Question

HELP PLEASE 30 POINTS

2x-3y=8 x-3y=8. solve with linear composition

Answer 1

Answer:

(0,-8/3)

Step-by-step explanation:

2x-3y=8

x-3y=8

Multiply the second equation by -1 and add together

2x-3y=8

-x+3y=-8

---------------------

x +0y =0

x=0

Now we can find y

2x -3y =8

0-3y =8

Divide by -3

-3y/-3 = 8/-3

y = -8/3

(0,-8/3)

Answer 2

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The given equations are :

• $2x - 3y = 8$

• $x - 3y = 8$

now, let's substract second equation from first equation :

• $2x - 3y - (x - 3y) = 8 - 8$

• $2x - 3y - x + 3y = 0$

• $x = 0$

now, plug value of x as 0 in the second equation to find value of y :

• $x - 3y = 8$

• $0 - 3y = 8$

• $- 3y = 8$

• $y = - \dfrac{8}{3}$

So, the solution of given pair of linear equations is :

• $\boxed{ \boxed{0, - \frac{8}{3} }}$