Answer: Molarity when 25.0 g of the compound [tex]NaClO_{3}[/tex]is placed in 85.0 mL of solution is 294.12 M.
Explanation:
Given: Mass = 25.0 g
Volume = 85.0 mL (1 mL = 0.001 L) = 0.085 L
Molarity is the number of moles of a substance divided by volume in liter.
Hence, molarity of given solution is calculated as follows.
[tex]Molarity = \frac{mass}{Volume (in L)}[/tex]
Substitute the values into above formula as follows.
[tex]Molarity = \frac{mass}{volume (in L)}\\= \frac{25.0 g}{0.085 L}\\= 294.12 M[/tex]
Thus, we can conclude that molarity when 25.0 g of the compound [tex]NaClO_{3}[/tex]is placed in 85.0 mL of solution is 294.12 M.
