Question

a
what is the weight of air inside a spherical balloon
of radius 2 meters? The density of air is 1.29 kg /m^3
Spherical balloon​

Answer 1

m = 43.2 kg

Explanation:

volume of sphere = (4/3)pi(r)^3

= (4/3)(3.14)(2 m)^3

= 33.5 m^3

density = mass/volume

or solving for mass m,

m = (density)×(volume)

= (1.29 kg/m^3)(33.5 m^3)

= 43.2 kg

Answer 2

The weight of air inside this spherical balloon is equal to 423.75 Newton.

Given the following data:

• Density of air = 1.29 $kg /m^3$

• Radius of balloon = 2 meters

To determine the weight of air inside this spherical balloon:

First of all, we would calculate the volume of this spherical balloon by using this formula:

$Volume = \frac{4}{3} \pi r^3\\\\Volume = \frac{4}{3} \times 3.142 \times 2^3\\\\Volume = \frac{32 \times 3.142}{3}$

Volume = 33.52 cubic meters.

Next, we would calculate the mass of air contained in this spherical balloon:

$Mass = density \times volume\\\\Mass = 1.29 \times 33.52$

Mass = 43.24 kg

For the weight of air:

$Weight = mg\\\\Weight = 43.24 \times 9.8$

Weight = 423.75 Newton

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