Answer:
[tex] {f}^{ - 1} (x) = 2x - 8[/tex]
[tex] {f}^{ - 1} (4) = 0[/tex]
Step-by-step explanation:
[tex] y = \frac{1}{2} x + 4 = = = > \\y - 4 = \frac{1}{2} x = = = > \\ 2y - 8 = x = = > {f}^{ - 1} (x) = 2x - 8[/tex]
[tex] \frac{1}{2} x + 4 = 4 = = = > \\ \frac{1}{2} x = 0 = = = > x = 0[/tex]