Need help plz show all work

Answer:
The center of the circle is at the coordinate: (1,6)
Explaination:
To find the answer all you need to do is add the x values together and divide by two and add the y values together and divide by two:
[tex]\frac{5-3}{2} =1[/tex] (x-values)
[tex]\frac{5+7}{2} =6[/tex] (y-values)
Therfore the center is at point (1,6)
Answer:
(1, 6 )
Step-by-step explanation:
The centre of the circle is at the midpoint of the diameter
Given endpoints (x₁, y₁ ) and (x₂, y₂ ) then the midpoint is
( [tex]\frac{x_{1}+x_{2} }{2}[/tex], [tex]\frac{y_{1}+y_{2} }{2}[/tex] )
Here (x₁, y₁ ) = (- 3, 5) and (x₂, y₂ ) = (5, 7) , then
midpoint = ( [tex]\frac{-3+5}{2}[/tex], [tex]\frac{5+7}{2}[/tex] ) = ([tex]\frac{2}{2}[/tex], [tex]\frac{12}{2}[/tex] ) = (1, 6 )
The centre of the circle is (1, 6 )