Question

How many moles of hypomanganous acid, H3MnO4, are contained in 22.912 g?

Answer 1

Answer:

0.188mol

Explanation:

Using the formula as follows:

mole = mass/molar mass

Molar mass of hypomanganous acid, H3MnO4 = 1(3) + 55 + 16(4)

= 3 + 55 + 64

= 122g/mol

Mass of H3MnO4 is given as 22.912 g

Hence;

moles = 22.912 ÷ 122

number of moles = 0.188mol