Given:
In triangle ABC, AB = 30, BC = 16, AC = 34 and measure of angle B is 90 degrees.
To find:
The value of Sine of angle A.
Solution:
In a right angle triangle,
[tex]\sin\theta=\dfrac{Perpendicular}{Hypotenuse}[/tex]
In the given triangle ABC,
[tex]\sin A=\dfrac{BC}{AC}[/tex]
[tex]\sin A=\dfrac{16}{34}[/tex]
[tex]\sin A=\dfrac{8}{27}[/tex]
Therefore, the correct option is A.
