Given :
A 2.8 m ladder is to be laid against a wall so that the top of the ladder is 2 m up the wall.
To Find :
How far out from the base of the wall should the ladder be placed.
Solution :
We know, the angle between floor and height is 90° .
Now, length of ladder, l = 2.8 m .
Height of wall, h = 2 m .
Let, distance between base of the wall and ladder is b .
[tex]l^2 = h^2 + b^2\\\\b = \sqrt{l^2 - h^2}\\\\b = \sqrt{2.8^2 - 2^2}\ m\\\\b = 1.96 \ m[/tex]
Hence, this is the required solution.
