Question

x^2-64=0 solve for all real values of x

Answer 1

Hi there! Use the difference of two squares formula to solve the problem below:

$\large \boxed{ {x}^{2} - {y}^{2} = (x + y)(x - y)}$

From the equation, 64 comes from 8². Thus,

$\large{ {x}^{2} - 64 = 0} \\ \large{(x + 8)(x - 8) = 0}$

The question also asks you to solve for all real values. Thus,

$\large{x = 8, - 8}$

Answer

• x = 8,-8 are the real solutions to x²-64 = 0.