h(t)=(t+3)
2
+5h, left parenthesis, t, right parenthesis, equals, left parenthesis, t, plus, 3, right parenthesis, squared, plus, 5
¿Sobre qué intervalo tiene hhh una tasa de cambio promedio negativa?

Respuesta :

The function must have a negative rate of change at the point where t < 3

Equations and expressions

Given the equation expressed as;

  • [tex]h(t) = (t+3)^2 + 5[/tex]

For the function to have a negative rate of change then;

[tex]\frac{dh}{dt} < 0[/tex]

Differentiate the function:

[tex]2(t - 3) < 0\\2t-6 < 0\\t < 3[/tex]

Hence the function must have a negative rate of change at the point where t < 3

Learn more on rate of change here: https://brainly.com/question/8728504

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