Answer:
The probability that both Jun and Deron get hired=0.2
Step-by-step explanation:
Let
A=Jun
B=Deron
We are given that
The probability that Jun gets the job, P(A)=0.7
The probability that Deron gets the job, P(B)=0.4
The probability that at least one of them gets hired, [tex]P(A\cup B)=0.9[/tex]
We have to find the probability that both Jun and Deron get hired.
We know that
[tex]P(A\cup B)=P(A)+P(B)-P(A\cap B)[/tex]
Using the formula
[tex]0.9=0.7+0.4-P(A\cap B)[/tex]
[tex]P(A\cap B)=1.1-0.9[/tex]
[tex]P(A\cap B)=0.2[/tex]
Hence, the probability that both Jun and Deron get hired=0.2